K 个一组翻转链表
题目
思路
- 每轮探测是否有 K 个节点
- 翻转 head, tail
- 把翻转后的凭借回去。
Java
class Solution {
public ListNode reverseKGroup(ListNode head, int k) {
if (head == null || k <= 1) {
return head;
}
ListNode dummy = new ListNode(0, head);
ListNode pre = dummy;
while (true) {
ListNode tail = pre;
for (int i = 0; i < k; i ++) {
tail = tail.next;
if (tail == null) {
return dummy.next;
}
}
ListNode next = tail.next;
ListNode groupHead = pre.next;
reverse(groupHead, tail);
pre.next = tail;
groupHead.next = next;
pre = groupHead;
}
}
private void reverse(ListNode head, ListNode tail) {
ListNode prev = null;
ListNode cur = head;
ListNode stop = tail.next;
while(cur != stop) {
ListNode nxt = cur.next;
cur.next = prev;
prev = cur;
cur = nxt;
}
}
}