题目
思路
- O(1) 查询 (哈希表)
- 记录最近使用顺序 (链表)
- 需要组合哈希表 + 双向链表
Java 解法
class LRUCache {
private static class Node {
int key, val;
Node prev, next;
Node(int k, int v) {
key = k;
val = v;
}
}
private final int capacity;
private final Map<Integer, Node> map = new HashMap<>();
private final Node head = new Node(0, 0);
private final Node tail = new Node(0, 0);
public LRUCache(int capacity) {
this.capacity = capacity;
head.next = tail;
tail.prev = head;
}
public int get(int key) {
Node node = map.get(key);
if (node == null) {
return -1;
}
moveToHead(node);
return node.val;
}
public void put(int key, int value) {
Node node = map.get(key);
if (node != null) {
node.val = value;
moveToHead(node);
return;
}
Node n = new Node(key, value);
map.put(key, n);
addAfterHead(n);
if (map.size() > capacity) {
Node lru = removeTail();
map.remove(lru.key);
}
}
private void moveToHead(Node node) {
remove(node);
addAfterHead(node);
}
private void addAfterHead(Node node) {
node.prev = head;
node.next = head.next;
head.next.prev = node;
head.next = node;
}
private void remove(Node node) {
node.prev.next = node.next;
node.next.prev = node.prev;
}
private Node removeTail() {
Node node = tail.prev;
remove(node);
return node;
}
}